<font color='black' size='2' face='Arial, Helvetica, sans-serif'>Doug,
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<div>I'd say the crossing in your drawing was about either 30 degrees or 150 degrees, and since it could come in on either side, I'd have to look for both. I am not asking that the rules state which side the angle is measured from. My issue is that I am developing a two-step test that covers all the conditions in the Challenge, but in the steps I need to include something that rejects the intersections. I am OK with rejecting any line that is 70 degrees to 110 degrees on either side. If the intersecting line is straight, the test is a bit more robust. If each side is 70 to 110 degrees (a bent intersecting line), my two-step test might fail.</div>
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<div>Doing it "that's just wrong" way,</div>
<div>John Swindle</div>
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<div style="font-family:arial,helvetica;font-size:10pt;color:black">-----Original Message-----<br>
From: Doug Paradis <paradug@gmail.com><br>
To: John Swindle <swindle@compuserve.com><br>
Cc: DPRG <dprglist@lists.dprg.org><br>
Sent: Fri, Dec 8, 2017 11:52 pm<br>
Subject: Re: LF intersection angle rule<br>
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<div dir="ltr">John,
<div> In the challenge course, all the intersections are 90 degrees. The rule was written to allow crossing variations in the future. I'm thinking that 70-90 degrees would represent the smallest angle of the intersection. I not sure that is right, just the way I would interpret the angle. </div>
<div>if you saw an intersection that was like this:</div>
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<div>What angle would you say the intersection was? </div>
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<div>Regards,</div>
<div>Doug P.</div>
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<div class="aolmail_gmail_quote">On Fri, Dec 8, 2017 at 9:03 PM, John Swindle <span dir="ltr"><<a target="_blank" rel="noopener noreferrer" href="mailto:swindle@compuserve.com">swindle@compuserve.com</a>></span> wrote:<br>
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<div>Doug,</div>
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<div>The Line Following Challenge rules say "Intersections may cross with angles of 70 - 90 degrees." Doesn't that really mean 70 to 110 degrees? Is the intersecting line straight, or can it bend at the intersection?</div>
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<div>Thanks,</div>
<div>John Swindle</div>
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